Madonna to Perform 'Same Love' With Macklemore & Ryan Lewis at the Grammys - Rolling Stone
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Madonna to Perform ‘Same Love’ With Macklemore at the Grammys

Track is nominated for Song of the Year

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Madonna performs at Philips Arena on November 17th, 2012 in Atlanta, Georgia.

Chris McKay/WireImage

Madonna will hit the stage with Macklemore & Ryan Lewis at the 2014 Grammy Awards on Sunday. Us Weekly reports that the Material Girl will join the hip-hop duo on their LGBT equality anthem, “Same Love.”

The track is up for a Song of the Year Grammy – one of seven nominations this year for Macklemore & Ryan Lewis.

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The Recording Academy confirmed the rumors on Friday that Madonna would be performing at the awards show, joining a star-studded lineup already included Paul McCartney, Ringo Starr, Lorde, Katy Perry, Taylor Swift, John Legend and Keith Urban.

The performance schedule for Sunday also features many more of the awards show’s signature pairings, including Kendrick Lamar with Imagine Dragons, Robin Thicke with ChicagoStevie Wonder with Daft Punk (plus Nile Rodgers and Pharrell Williams), Metallica with concert pianist Lang Lang, Carole King with Sara Bareilles and Pink with fun. frontman Nate Ruess. Green Day frontman Billie Joe Armstrong will also be joining Miranda Lambert in a tribute to the recently-departed Everly Brothers’ Phil Everly.

The Grammy Awards will be broadcast live from Los Angeles’ Staples Center on CBS beginning at 8 p.m. EST on Sunday.

In This Article: Grammy Awards, Grammys 2014


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